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Old 05-20-2009, 11:05 AM   #1
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Need Engineering Help

Well it has been a long time since I have taken a class going over this and am looking for a little help. I am trying to find the tension in each cable. My cousin was asking me about it and I just can't remember for anything. Each Circle is a Pulley.
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Old 05-20-2009, 01:19 PM   #2
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I know someone on here must know something about engineering... if nothing else I am going to see if I can dust off some of my old books and flip thru them.
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Old 05-20-2009, 01:21 PM   #3
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I usually do better with multiple choice.
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Old 05-20-2009, 01:21 PM   #4
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Old 05-20-2009, 01:21 PM   #5
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Quote:
Originally Posted by mar_ga_rita View Post
I know someone on here must know something about engineering... if nothing else I am going to see if I can dust off some of my old books and flip thru them.
they're probably at work right now...might get some responses tonite
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Old 05-20-2009, 01:26 PM   #6
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Quote:
Originally Posted by tcBob View Post
they're probably at work right now...might get some responses tonite
haha yea I am trying to get some young buck though... figure they are still in classes
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Old 05-20-2009, 02:07 PM   #7
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maybe?

I know this is a statics problem, so all the forces are equal. The lengths of the ropes don't really matter since they are considered weightless.

Tension of Cable 3 (L3) is just the weight.
Ft3=60lbs.

Tension of Cable 2 (L2) is done by setting up a right triangle to get the tension force at that angle. So Cos(180-theta1)=Wt/Ft2==>Ft2=60/Cos(42.4deg)=81.25lbs tension for Length 2.
Ft2=81.25lbs

Tension in cable 3 is still 60 lbs down, and found by using the theta2 and using it to get another right triangle with cable 3 to get equilibrium (I think). cos(15.6)=60/Ft1==>Ft1=60/cos(15.6)=62.29lbs
Ft1=62.29lbs

(It's been 6 years since I've had this class, so better double check the answer)
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Old 05-20-2009, 02:15 PM   #8
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summation of the forces. Find all the forces in the x and y direction, equate and set each equal to zero.
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Old 05-20-2009, 02:18 PM   #9
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my bad, i thought they said t1, t2, t3. not lengths.
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Old 05-20-2009, 02:18 PM   #10
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Quote:
Originally Posted by lifesaflaw123 View Post
summation of the forces. Find all the forces in the x and y direction, equate and set each equal to zero.

Thats right, hopefully I did it correctly above.
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Old 05-20-2009, 02:24 PM   #11
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Quote:
Originally Posted by trtripoli View Post
I know this is a statics problem, so all the forces are equal. The lengths of the ropes don't really matter since they are considered weightless.

Tension of Cable 3 (L3) is just the weight.
Ft3=60lbs.

Tension of Cable 2 (L2) is done by setting up a right triangle to get the tension force at that angle. So Cos(180-theta1)=Wt/Ft2==>Ft2=60/Cos(42.4deg)=81.25lbs tension for Length 2.
Ft2=81.25lbs

Tension in cable 3 is still 60 lbs down, and found by using the theta2 and using it to get another right triangle with cable 3 to get equilibrium (I think). cos(15.6)=60/Ft1==>Ft1=60/cos(15.6)=62.29lbs
Ft1=62.29lbs

(It's been 6 years since I've had this class, so better double check the answer)
That seems correct... It has been so long since I have even worked a statics problem lol
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Old 05-20-2009, 03:01 PM   #12
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If the pulleys are frictionless, the tension is the same trough the whole cable.
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Old 05-20-2009, 04:11 PM   #13
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I took statics last semester so I should know how to do this.

Unfortunately I slept thru half of my classes, so I don't know how to do this.
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Old 05-20-2009, 04:52 PM   #14
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Quote:
Originally Posted by pittim View Post
I took statics last semester so I should know how to do this.

Unfortunately I slept thru half of my classes, so I don't know how to do this.
I didn't know how to do statics til I got threw dynmaics.
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Old 05-20-2009, 05:12 PM   #15
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Quote:
Originally Posted by trtripoli View Post
I didn't know how to do statics til I got threw dynmaics.
yeah, all I know is EF=0 and EM=0.

How you get to that I have noooooooooooo idea haha.
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Old 05-20-2009, 05:21 PM   #16
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Quote:
Originally Posted by pittim View Post
I took statics last semester so I should know how to do this.

Unfortunately I slept thru half of my classes, so I don't know how to do this.
haha I take statics next quarter. At my school its an 80% fail rate
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Old 05-20-2009, 05:47 PM   #17
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I still say its the same tension ( L1=L2=L3 ) those are fixed pulleys, frictionless with a cable with negligible mass.
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Old 05-20-2009, 06:20 PM   #18
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Quote:
Originally Posted by jdkeller View Post
haha I take statics next quarter. At my school its an 80% fail rate
Have fun!

I took it twice. First time was with this teacher that gave really fucking complicated problems and couldn't teach for shit. I dropped the class immediately after taking the 2nd test (literally, once I got back to my room I dropped it haha.) I picked up a different teacher for my send hack at the class. At least 60% of the class was people that had the guy I had for my first whack at the class.
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Old 05-20-2009, 06:26 PM   #19
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Quote:
Originally Posted by epa4wd View Post
I still say its the same tension ( L1=L2=L3 ) those are fixed pulleys, frictionless with a cable with negligible mass.
x2
Those pulleys are changing direction of force and not multiplying it so T1=T2=T3.
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Old 05-20-2009, 07:08 PM   #20
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Quote:
Originally Posted by epa4wd View Post
I still say its the same tension ( L1=L2=L3 ) those are fixed pulleys, frictionless with a cable with negligible mass.
Quote:
Originally Posted by EEtaco View Post
x2
Those pulleys are changing direction of force and not multiplying it so T1=T2=T3.
I'm with these guys. Those pulleys have no mechanical advantage so you might as well be lifting that weight straight up. The tension in all the cables is the same.
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