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Old 02-29-2012, 11:18 AM   #1
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Any Chemistry people?

Hey guys, I'm not doing to well in Chemistry at the moment. I have a huge test tomorrow that could determine my grade, it's just 11th grade Chemistry. Anyone that might be able to help please do! It's writing and balancing equations. I ended up getting only 4 questions out of 15 right on a practice sheet and my test is tomorrow, PLEASE HELP IF POSSIBLE!
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Old 02-29-2012, 11:46 AM   #2
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Can you post up the questions? I can help.
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Old 02-29-2012, 11:48 AM   #3
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like she said post up questions...im alright at balancing equations...if you need help with stoichiometry i can definitely help haha
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Old 02-29-2012, 02:08 PM   #4
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Unhappy

Thanks guys! Here's a few of the ones I'm getting caught up on.

1. (NH4)2 CO3 + Na2 OH ---> Na2 CO3 + NH3 + H2O

2. 2C2 H5 OH + O2 ---> CO2 + H2O

3. K3 PO4 + BaCl2 ----->

4. CH4 + O2 ----> CO2 +

5. Cd(NO3)2 + NH4 Cl ---->

6. NaClO3 ---> NaCl + O2
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Old 02-29-2012, 02:25 PM   #6
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Quote:
Originally Posted by UNDEAD1153 View Post
Thanks guys! Here's a few of the ones I'm getting caught up on.

1. (NH4)2 CO3 + Na2 OH ---> Na2 CO3 + NH3 + H2O

2. 2C2 H5 OH + O2 ---> CO2 + H2O

3. K3 PO4 + BaCl2 ----->

4. CH4 + O2 ----> CO2 +

5. Cd(NO3)2 + NH4 Cl ---->

6. NaClO3 ---> NaCl + O2
all of these are just basic math! Write out how much of each element are on both sides, and find the way to balance them!
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Old 02-29-2012, 02:25 PM   #7
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sees what you did there.
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Prayers and Support section: "Offer your emotional support to members going through tough times"
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Old 02-29-2012, 02:27 PM   #8
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Quote:
Originally Posted by UNDEAD1153 View Post
Thanks guys! Here's a few of the ones I'm getting caught up on.

1. (NH4)2 CO3 + Na2 OH ---> Na2 CO3 + NH3 + H2O

2. 2C2 H5 OH + 4O2 ---> 4CO2 + 6H2O

3. K3 PO4 + BaCl2 ----->

4. CH4 + O2 ----> CO2 +

5. Cd(NO3)2 + NH4 Cl ---->

6. 2NaClO3 ---> 2NaCl + 3O2
Here's what little bit I remember from Chemistry

If I had time to think, I could probably get the others (#1 is just basic math but I don't have time to mess with it, the others follow rules which I don't remember). Good luck!
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Old 02-29-2012, 02:42 PM   #9
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Sorry.....my teacher actually believes he is God and his actual motto is "If you dont know it, know it." And I do need support.....maybe different connotation of support but still need support....and this test determines my grade, also wether or not I'll have my truck for the next 6 weeks.
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Old 02-29-2012, 02:53 PM   #10
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I agree that this should be in the prayers and support section! Anyway, puggas answers look right and I think the first one should just have a 2 in front of nh3 on the right side. I think. Anyway, just make a list of the elements on each side, count the number of each on each side and then basic math. Or just use trial and error until it balances...
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Old 02-29-2012, 02:59 PM   #11
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Quote:
Originally Posted by UNDEAD1153 View Post
Thanks guys! Here's a few of the ones I'm getting caught up on.

1. (NH4)2 CO3 + Na2 OH ---> Na2 CO3 + NH3 + H2O

2. 2C2 H5 OH + O2 ---> CO2 + H2O

3. K3 PO4 + BaCl2 ----->

4. CH4 + O2 ----> CO2 + H4

5. Cd(NO3)2 + NH4 Cl ---->

6. NaClO3 ---> NaCl + O2
2 K3PO4 + 3 BaCl2 -> Ba3(PO4)2 + 6 KCl
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Old 02-29-2012, 03:02 PM   #12
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If you hadn't waited until the night before the test!!

Very helpful information here: http://www.webqc.org/balance.php

Use these to check your work and keep going back until you understand what you've done with each one.

For the first one, there's no such thing as Na2OH. Na is +1 and always +1. O and H are VERY happy together and for your purpose should always be split from a compound together--as a -1. So you should have NaOH there.

After that you're just going to add a coefficient in front of some of the compounds in the equation.
If you look at the first compound, you know there HAVE to be at least 2 N's. Therefore, you can start by adding a 2 in front of the NH3.
You also have 2 Na's. You can put a 2 in front of the NaOH.
Now, your N's, C's and Na's are balanced. How about the O's and H's? Nope? Right now you've got 5 O's on the left and only 4 on the right. If you put a 2 in front of that H2O that'd balance the O's. If you count the H's now, that should do it. Yup, 10 H's on each side.

For #2, Technically the equation as written (2C2H5OH + 6H2O ~~> 4CO2 + 6H2O is not correct, since it can be reduced to C2H5OH + 3O2 ~~> 2CO2 + 3H2O (dividing everything by 2))

Perhaps you can collect some brownie, or even bonus points by noting that if it appears on the test.

More in a bit.
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Old 02-29-2012, 03:14 PM   #13
I phucking hate people >:(
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ha, I have a gen chem 1 test tomorrow as well.

chem wasn't a requirement for my highschool though. I wonder why...

anyhoo, you have a ton of resources at your disposal man! Google, youtube, textbooks, I've practically been teaching myself cuz I cannot concentrate in that class. Haha
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Old 02-29-2012, 03:20 PM   #14
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Once again, sorry for it being in the wrong section, didn't know where to put it. Anyways, thanks for the help, ive been studying just for this test the past 3 days and i still don't completely understand it. I'll keep working at it. I can get the easy ones no problem but the difficult ones, I'm lost.
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Old 02-29-2012, 03:24 PM   #15
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Old 02-29-2012, 03:27 PM   #16
I'm a zit. Get it?
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Hey guys, I'm not doing to well in Chemistry at the moment.
join the club
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Old 02-29-2012, 03:30 PM   #17
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The trick to figuring out what the products should be is getting a feel for how to split the reactant molecules up.


Your hint is going to be to look for an atom in either the first two or third and second-to last columns on the periodic table--they'll be a dead giveaway: Column 1 (aka 1A) will always be a +1. column 2 (aka 2A) will be +2. The last column (8A) is noble gases that don't react. The second to last column (7A) will be -1, and the third to last column (6A) will be -2. Those will tell you how to split apart the reactants.

for # 3:
K3PO4 is split into 3K+1 and PO4-3 (K is your hint--it's always +1 and there are three of them you know that PO4 will be -3) (hard to do without super and sub scripts!)--
BaCl2 is Ba+2 and 2 Cl- (since Cl is always -1 and there are two of them you know without even looking that Ba is going to be +2)

Now, take your pluses and swap.

K+ goes over to Cl-. They are very happy together. They make one product.
Ba2+ goes over to hang with the PO4-3--but it's like a little equation right in itself that you have to balance. What you do is put a 3 after the Ba and a 2 after the (PO4) to make Ba3(PO4)2.

Now you've got the products. Let's balance the whole damn thing.

K3PO4 + BaCl2 ~~> KCl + Ba3(PO4)2

Three K's on the left--put a 3 in front of KCL

K3PO4 + BaCl2 ~~>3 KCl + Ba3(PO4)2

That gives us a mismatch on the chloride now though (2Cl on the left and 3 on the right--so let's put a 3 in front of BaCl2 and go ahead and double the KCl to put it right:

K3PO4 + 3 BaCl2 ~~>6 KCl + Ba3(PO4)2

So now our Ba's and Cl's are right but the K's are out of whack. Easy fix, just put a 2 in front of the K3PO4:

2K3PO4 + 3 BaCl2 ~~>6 KCl + Ba3(PO4)2

Now if we count everything up, we have 6 K's on the left, 6 on the right.
2P's
8O's
3Ba's
and 6 Cl's

Yay! (I suppose it's more like *whew*)
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Old 02-29-2012, 03:40 PM   #18
6 Double 5 3 2 1
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I helped mntbiker2008 with his college chemistry class:

OJ + Vodka = screwdriver

Seagrams 7+7UP = 7&7

Guinness + Blue Moon = Dark Side of the Moon

Only chemistry I remembered from college
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Old 02-29-2012, 03:43 PM   #19
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Thank you! That really helped! I went to my teacher after school (he made no sense at all even one on one) and he said if we can just balance the equations, we should do fine. Once again, thank you, I'll be studying all night, hopefully it'll click.
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Old 02-29-2012, 03:43 PM   #20
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Quote:
Originally Posted by thebigk View Post
I helped mntbiker2008 with his college chemistry class:

OJ + Vodka = screwdriver

Seagrams 7+7UP = 7&7

Guinness + Blue Moon = Dark Side of the Moon

Only chemistry I remembered from college
Hahahaha dude I'm 16.......
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