1st Gen Lunchtable Thread - General Discussion

That's a funny name for bedliner

 

What if you clearcoat your bedliner?

 

Black ice bed liner... You could probably sell that to the same jeep guys that buy that vinyl wrap that looks like the inside of a pocket watch

 

https://www.instagram.com/reel/CpL6I30grys/?igshid=YmMyMTA2M2Y=

 

Damn, and it's scratch and sniff?

 

I forgot how unfun it is to get to the two top bell housing bolts on a 5vz

 

Spent 20 minutes to give it a wipe down with a product like Meguiar's Ultimate Quick Wax before hitting the trail. Then branches will bounce off the slick finish without scratching.

 

I removed the exhaust pipe that was in the way. It unwinds from the bottom.

 

@treyus30 @JKO1998 anyone else that's taken fluid power courses... looking at this

I need to use nt. n is my speed in min^-1. Do I just multiply my n by .85?



My ultimate goal is to figure out the power required to turn a hydraulic pump, I am trying to use this basic calculations sheet I found.
Am I correct in trying to use the P IN equation?

 

If you know what power out you want you just divide it by the n sub t to find the power you need to put in. All depends on the efficiency of your pump.


If im seeing it right anyway.

 

Hey for once I could have answered one of those. Volumetric efficiency is how we tune with the Haltech

 

Correct me if I'm wrong, fluids was awhile ago

 

No, you're right I believe. I was over here trying to find out why the formulas are labelled with English bu the manual is in Italian

 

Okay maybe you can help me work through this then. (My boss does everything in imperial so pardon my metric conversions, most of the pumps and shit we buy are European so I go by their measurements and loosely covert em for my boss)

What I want from my pump is 75lpm at 150bar. So I divide the product of those by 600 and get 18.75kW. Now I'm assuming the n sub t is revolutions of the pump I choose, and that's dependent on the rpms of the engine turning it (in this case peak torque is 3000rpm. But dividing 18.75 by (3000x.85) gives me .0073 and I don't think I'm doing something correctly because i dont know what that means lol.

 

Lol cause it's an Italian company that just ran their words through a shitty Google translate ripoff to provide an "english" version.

 

What they said.

Efficiency is unitless though.

I think about it logically: you need more Pin to get a Pout, so dividing by a fraction will get you a larger value (Pin)

 

Are air volume calculations compatible to fluid volume calculations?


Pardon me if that's a dumb question, I only ask cause air is squishable and liquids are not anywhere near as squishable

 

https://hydraulicsonline.com/technical-knowledge-hub-news/hydraulic-calculations-and-formulas/

You gotta figure out the right efficiency

 

So I'm incorrect in treating that .85 efficiency rating the same way I would treat a coefficient of friction?

 

That's the article I needed to read, thank you