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Any Chemistry people?

Discussion in 'Prayers & Support' started by UNDEAD1153, Feb 29, 2012.

  1. Feb 29, 2012 at 10:18 AM
    #1
    UNDEAD1153

    UNDEAD1153 [OP] Well-Known Member

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    Hey guys, I'm not doing to well in Chemistry at the moment. I have a huge test tomorrow that could determine my grade, it's just 11th grade Chemistry. Anyone that might be able to help please do! It's writing and balancing equations. I ended up getting only 4 questions out of 15 right on a practice sheet and my test is tomorrow, PLEASE HELP IF POSSIBLE!
     
  2. Feb 29, 2012 at 10:46 AM
    #2
    Squisha

    Squisha Well-Known Member

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    Can you post up the questions? I can help.
     
  3. Feb 29, 2012 at 10:48 AM
    #3
    113tac

    113tac Well-Known Member

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    like she said post up questions...im alright at balancing equations...if you need help with stoichiometry i can definitely help haha
     
  4. Feb 29, 2012 at 1:08 PM
    #4
    UNDEAD1153

    UNDEAD1153 [OP] Well-Known Member

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    Thanks guys! Here's a few of the ones I'm getting caught up on.

    1. (NH4)2 CO3 + Na2 OH ---> Na2 CO3 + NH3 + H2O

    2. 2C2 H5 OH + O2 ---> CO2 + H2O

    3. K3 PO4 + BaCl2 ----->

    4. CH4 + O2 ----> CO2 +

    5. Cd(NO3)2 + NH4 Cl ---->

    6. NaClO3 ---> NaCl + O2
     
  5. Feb 29, 2012 at 1:22 PM
    #5
    KPT

    KPT sees what you did there.

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    In the prayers and support section? :facepalm:
     
  6. Feb 29, 2012 at 1:25 PM
    #6
    Konaborne

    Konaborne Pineapples on pizza Hawaiian does not it make.

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    all of these are just basic math! Write out how much of each element are on both sides, and find the way to balance them!
     
  7. Feb 29, 2012 at 1:25 PM
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    KPT

    KPT sees what you did there.

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    Prayers and Support section: "Offer your emotional support to members going through tough times"
     
  8. Feb 29, 2012 at 1:27 PM
    #8
    Pugga

    Pugga Pasti-Dip Free Since 1983

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    Here's what little bit I remember from Chemistry :eek:

    If I had time to think, I could probably get the others (#1 is just basic math but I don't have time to mess with it, the others follow rules which I don't remember). Good luck!
     
  9. Feb 29, 2012 at 1:42 PM
    #9
    UNDEAD1153

    UNDEAD1153 [OP] Well-Known Member

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    Sorry.....my teacher actually believes he is God and his actual motto is "If you dont know it, know it." And I do need support.....maybe different connotation of support but still need support....and this test determines my grade, also wether or not I'll have my truck for the next 6 weeks.
     
  10. Feb 29, 2012 at 1:53 PM
    #10
    H Bomb

    H Bomb Well-Known Member

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    I agree that this should be in the prayers and support section! Anyway, puggas answers look right and I think the first one should just have a 2 in front of nh3 on the right side. I think. Anyway, just make a list of the elements on each side, count the number of each on each side and then basic math. Or just use trial and error until it balances...
     
  11. Feb 29, 2012 at 1:59 PM
    #11
    Konaborne

    Konaborne Pineapples on pizza Hawaiian does not it make.

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    2 K3PO4 + 3 BaCl2 -> Ba3(PO4)2 + 6 KCl
     
  12. Feb 29, 2012 at 2:02 PM
    #12
    Squisha

    Squisha Well-Known Member

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    If you hadn't waited until the night before the test!!

    Very helpful information here: http://www.webqc.org/balance.php

    Use these to check your work and keep going back until you understand what you've done with each one.

    For the first one, there's no such thing as Na2OH. Na is +1 and always +1. O and H are VERY happy together and for your purpose should always be split from a compound together--as a -1. So you should have NaOH there.

    After that you're just going to add a coefficient in front of some of the compounds in the equation.
    If you look at the first compound, you know there HAVE to be at least 2 N's. Therefore, you can start by adding a 2 in front of the NH3.
    You also have 2 Na's. You can put a 2 in front of the NaOH.
    Now, your N's, C's and Na's are balanced. How about the O's and H's? Nope? Right now you've got 5 O's on the left and only 4 on the right. If you put a 2 in front of that H2O that'd balance the O's. If you count the H's now, that should do it. Yup, 10 H's on each side.

    For #2, Technically the equation as written (2C2H5OH + 6H2O ~~> 4CO2 + 6H2O is not correct, since it can be reduced to C2H5OH + 3O2 ~~> 2CO2 + 3H2O (dividing everything by 2))

    Perhaps you can collect some brownie, or even bonus points by noting that if it appears on the test.

    More in a bit.
     
  13. Feb 29, 2012 at 2:14 PM
    #13
    ink junky

    ink junky I phucking hate people >:(

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    ha, I have a gen chem 1 test tomorrow as well.

    chem wasn't a requirement for my highschool though. :confused: I wonder why...

    anyhoo, you have a ton of resources at your disposal man! Google, youtube, textbooks, I've practically been teaching myself cuz I cannot concentrate in that class. Haha
     
  14. Feb 29, 2012 at 2:20 PM
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    UNDEAD1153

    UNDEAD1153 [OP] Well-Known Member

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    Once again, sorry for it being in the wrong section, didn't know where to put it. Anyways, thanks for the help, ive been studying just for this test the past 3 days and i still don't completely understand it. I'll keep working at it. I can get the easy ones no problem but the difficult ones, I'm lost.
     
  15. Feb 29, 2012 at 2:24 PM
    #15
    Steves104x4

    Steves104x4 Well-Known Member

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    BUCKLE UP! It makes it harder for Aliens to pull you out of your Truck.
  16. Feb 29, 2012 at 2:27 PM
    #16
    jgwheeler17

    jgwheeler17 I'm a zit. Get it?

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    join the club
     
  17. Feb 29, 2012 at 2:30 PM
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    Squisha

    Squisha Well-Known Member

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    The trick to figuring out what the products should be is getting a feel for how to split the reactant molecules up.


    Your hint is going to be to look for an atom in either the first two or third and second-to last columns on the periodic table--they'll be a dead giveaway: Column 1 (aka 1A) will always be a +1. column 2 (aka 2A) will be +2. The last column (8A) is noble gases that don't react. The second to last column (7A) will be -1, and the third to last column (6A) will be -2. Those will tell you how to split apart the reactants.

    for # 3:
    K3PO4 is split into 3K+1 and PO4-3 (K is your hint--it's always +1 and there are three of them you know that PO4 will be -3) (hard to do without super and sub scripts!)--
    BaCl2 is Ba+2 and 2 Cl- (since Cl is always -1 and there are two of them you know without even looking that Ba is going to be +2)

    Now, take your pluses and swap.

    K+ goes over to Cl-. They are very happy together. They make one product.
    Ba2+ goes over to hang with the PO4-3--but it's like a little equation right in itself that you have to balance. What you do is put a 3 after the Ba and a 2 after the (PO4) to make Ba3(PO4)2.

    Now you've got the products. Let's balance the whole damn thing.

    K3PO4 + BaCl2 ~~> KCl + Ba3(PO4)2

    Three K's on the left--put a 3 in front of KCL

    K3PO4 + BaCl2 ~~>3 KCl + Ba3(PO4)2

    That gives us a mismatch on the chloride now though (2Cl on the left and 3 on the right--so let's put a 3 in front of BaCl2 and go ahead and double the KCl to put it right:

    K3PO4 + 3 BaCl2 ~~>6 KCl + Ba3(PO4)2

    So now our Ba's and Cl's are right but the K's are out of whack. Easy fix, just put a 2 in front of the K3PO4:

    2K3PO4 + 3 BaCl2 ~~>6 KCl + Ba3(PO4)2

    Now if we count everything up, we have 6 K's on the left, 6 on the right.
    2P's
    8O's
    3Ba's
    and 6 Cl's

    Yay! (I suppose it's more like *whew*)
     
  18. Feb 29, 2012 at 2:40 PM
    #18
    thebigk

    thebigk 6 Double 5 3 2 1

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    I helped mntbiker2008 with his college chemistry class:

    OJ + Vodka = screwdriver

    Seagrams 7+7UP = 7&7

    Guinness + Blue Moon = Dark Side of the Moon

    Only chemistry I remembered from college :D
     
  19. Feb 29, 2012 at 2:43 PM
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    UNDEAD1153

    UNDEAD1153 [OP] Well-Known Member

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    Thank you! That really helped! I went to my teacher after school (he made no sense at all even one on one) and he said if we can just balance the equations, we should do fine. Once again, thank you, I'll be studying all night, hopefully it'll click.
     
  20. Feb 29, 2012 at 2:43 PM
    #20
    UNDEAD1153

    UNDEAD1153 [OP] Well-Known Member

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    Hahahaha dude I'm 16.......
     
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